1. Find the molar mass of Fe₂O₃:
* Iron (Fe) has a molar mass of 55.845 g/mol.
* Oxygen (O) has a molar mass of 15.9994 g/mol.
* Fe₂O₃ has 2 iron atoms and 3 oxygen atoms: (2 * 55.845 g/mol) + (3 * 15.9994 g/mol) = 159.6882 g/mol
2. Use the formula: moles = mass / molar mass
* moles = 231 g / 159.6882 g/mol
* moles ≈ 1.45 mol
Therefore, there are approximately 1.45 moles of Fe₂O₃ in 231 g of the compound.
