1. Write the balanced chemical equation for the combustion of octane:

C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O

2. Determine the mole ratio between octane and water:

From the balanced equation, we see that 1 mole of octane (C₈H₁₈) produces 9 moles of water (H₂O).

3. Calculate the moles of water produced:

* Use the mole ratio to convert moles of octane to moles of water:

0.468 mol C₈H₁₈ * (9 mol H₂O / 1 mol C₈H₁₈) = 4.212 mol H₂O

Therefore, 4.212 moles of water are produced when 0.468 moles of octane are burned.