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  • Tungsten Production: Calculating Moles from Hydrogen and WO3
    Here's how to solve this problem:

    1. Balanced Chemical Equation

    The balanced chemical equation for the reaction is:

    3H₂(g) + WO₃(s) → W(s) + 3H₂O(g)

    2. Mole Ratio

    The balanced equation shows that 3 moles of hydrogen (H₂) react to produce 1 mole of tungsten (W).

    3. Calculation

    * Start with the moles of hydrogen: 2405 moles H₂

    * Use the mole ratio from the balanced equation: (1 mole W / 3 moles H₂)

    * Multiply to find moles of tungsten: 2405 moles H₂ * (1 mole W / 3 moles H₂) = 801.67 moles W

    Answer: You can produce approximately 801.67 moles of tungsten from 2405 moles of hydrogen and excess WO₃.

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