1. Find the molar mass of magnesium nitrate:
* Mg: 24.31 g/mol
* N: 14.01 g/mol (x 2 = 28.02 g/mol)
* O: 16.00 g/mol (x 6 = 96.00 g/mol)
Total molar mass of Mg(NO₃)₂ = 24.31 + 28.02 + 96.00 = 148.33 g/mol
2. Calculate the moles of magnesium nitrate:
* moles = mass / molar mass
* moles = 9.00 g / 148.33 g/mol
* moles = 0.0607 mol Mg(NO₃)₂
3. Determine the total number of atoms per molecule:
* One molecule of Mg(NO₃)₂ contains:
* 1 magnesium atom (Mg)
* 2 nitrogen atoms (N)
* 6 oxygen atoms (O)
* Total = 9 atoms
4. Calculate the moles of atoms:
* moles of atoms = moles of Mg(NO₃)₂ * atoms per molecule
* moles of atoms = 0.0607 mol * 9 atoms/molecule
* moles of atoms = 0.546 mol
Therefore, there are approximately 0.546 moles of atoms in 9.00 g of magnesium nitrate.
