1. Understand the Reaction

The reaction between HCl (hydrochloric acid) and NaOH (sodium hydroxide) is a neutralization reaction:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

2. Stoichiometry

The balanced equation shows a 1:1 mole ratio between HCl and NaOH. This means that one mole of HCl reacts completely with one mole of NaOH.

3. Calculate Moles of NaOH

* Use the molarity and volume of NaOH to find the moles:

* Moles NaOH = Molarity × Volume (in liters)

* Moles NaOH = 0.300 M × 0.0531 L = 0.01593 moles

4. Calculate Moles of HCl

* Since the mole ratio is 1:1, the moles of HCl are equal to the moles of NaOH:

* Moles HCl = 0.01593 moles

5. Calculate HCl Concentration

* Concentration (Molarity) = Moles / Volume (in liters)

* Concentration HCl = 0.01593 moles / 0.0150 L = 1.062 M

Therefore, the concentration of the HCl solution is 1.062 M.