Understanding Gay-Lussac's Law
Gay-Lussac's Law states that the pressure of a gas is directly proportional to its absolute temperature when the volume is held constant. Mathematically, this is expressed as:
P₁/T₁ = P₂/T₂
Where:
* P₁ = Initial pressure
* T₁ = Initial temperature (in Kelvin)
* P₂ = Final pressure
* T₂ = Final temperature (in Kelvin)
Solving the Problem
1. Convert temperatures to Kelvin:
* T₁ = 20.0°C + 273.15 = 293.15 K
* T₂ = 40.0°C + 273.15 = 313.15 K
2. Plug the values into Gay-Lussac's Law equation:
* 660 torr / 293.15 K = P₂ / 313.15 K
3. Solve for P₂ (the final pressure):
* P₂ = (660 torr * 313.15 K) / 293.15 K
* P₂ ≈ 705 torr
Therefore, the pressure will change from 660 torr to approximately 705 torr.
