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  • Calculating the Molar Mass of Lead Acetate (Pb(CH3COO)2)
    Here's how to calculate the molar mass of lead acetate, Pb(CH₃COO)₂:

    1. Identify the Elements and Their Atomic Masses

    * Lead (Pb): 207.2 g/mol

    * Carbon (C): 12.01 g/mol

    * Hydrogen (H): 1.01 g/mol

    * Oxygen (O): 16.00 g/mol

    2. Count the Number of Atoms of Each Element

    * Lead (Pb): 1

    * Carbon (C): 2 x 2 = 4

    * Hydrogen (H): 3 x 2 = 6

    * Oxygen (O): 2 x 2 + 2 = 6

    3. Calculate the Total Mass

    * Pb: 1 x 207.2 g/mol = 207.2 g/mol

    * C: 4 x 12.01 g/mol = 48.04 g/mol

    * H: 6 x 1.01 g/mol = 6.06 g/mol

    * O: 6 x 16.00 g/mol = 96.00 g/mol

    4. Add Up the Individual Masses

    207.2 g/mol + 48.04 g/mol + 6.06 g/mol + 96.00 g/mol = 357.3 g/mol

    Therefore, the molar mass of lead acetate, Pb(CH₃COO)₂, is 357.3 g/mol.

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