1. Calculate the moles of CaCl₂:
* Molar mass of CaCl₂: 40.08 g/mol (Ca) + 2 * 35.45 g/mol (Cl) = 110.98 g/mol
* Moles of CaCl₂: (347 g) / (110.98 g/mol) = 3.13 mol
2. Calculate the moles of ions:
* Each CaCl₂ molecule dissociates into 3 ions: 1 Ca²⁺ ion and 2 Cl⁻ ions.
* Total moles of ions: 3.13 mol CaCl₂ * 3 ions/mol = 9.39 mol ions
3. Calculate the number of ions:
* Avogadro's number: 6.022 x 10²³ ions/mol
* Total number of ions: 9.39 mol ions * 6.022 x 10²³ ions/mol = 5.66 x 10²⁴ ions
Therefore, there are approximately 5.66 x 10²⁴ ions present in 347 g of CaCl₂.
