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  • Freezing Point Depression Calculation: AlCl3 in Water - Chemistry Problem
    Here's how to calculate the freezing point change of the solution:

    Understanding the Concepts

    * Freezing Point Depression: The freezing point of a solvent is lowered when a solute is dissolved in it. This is a colligative property, meaning it depends on the concentration of solute particles, not their identity.

    * Van't Hoff Factor (i): This factor accounts for the number of ions a solute dissociates into when dissolved in a solvent. Aluminum chloride (AlCl₃) dissociates into four ions: one aluminum ion (Al³⁺) and three chloride ions (Cl⁻). So, its van't Hoff factor (i) is 4.

    * Freezing Point Depression Equation: ΔTf = i * Kf * m

    * ΔTf is the change in freezing point

    * i is the van't Hoff factor

    * Kf is the freezing point depression constant of the solvent (for water, Kf = 1.86 °C/m)

    * m is the molality of the solution (moles of solute per kilogram of solvent)

    Calculations

    1. Molality (m):

    * You have 1 mole of AlCl₃ dissolved in 1000 g (1 kg) of water.

    * Therefore, molality (m) = 1 mol / 1 kg = 1 mol/kg

    2. Freezing Point Change (ΔTf):

    * ΔTf = i * Kf * m

    * ΔTf = 4 * 1.86 °C/m * 1 mol/kg

    * ΔTf = 7.44 °C

    Conclusion

    The freezing point of the solution will decrease by 7.44 °C compared to the freezing point of pure water (0 °C). This means the solution will freeze at approximately -7.44 °C.

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