1. Balanced Chemical Equation:

The reaction you're describing is the combustion of a carbon-containing compound (like a hydrocarbon) to produce carbon dioxide (CO2) and water (H2O). Since we only care about the oxygen and carbon dioxide, we can simplify the equation:

C + O2 → CO2

2. Mole Ratios:

The balanced equation shows that 1 mole of O2 produces 1 mole of CO2.

3. Molar Mass:

* The molar mass of O2 is 32 g/mol (16 g/mol for each oxygen atom).

* The molar mass of CO2 is 44 g/mol (12 g/mol for carbon and 32 g/mol for oxygen).

4. Calculation:

* Step 1: Calculate the moles of O2:

moles of O2 = mass of O2 / molar mass of O2 = 8.0 g / 32 g/mol = 0.25 mol

* Step 2: Since the mole ratio of O2 to CO2 is 1:1, you have 0.25 mol of CO2 produced.

* Step 3: Calculate the mass of CO2:

mass of CO2 = moles of CO2 * molar mass of CO2 = 0.25 mol * 44 g/mol = 11 g

Answer: 11 grams of CO2 are used when 8.0 grams of O2 are produced.