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  • Calculating Oxygen Oxidation State in O₂PtF₆: A Step-by-Step Guide
    Here's how to determine the oxidation state of oxygen in O₂PtF₆:

    Understanding Oxidation States

    * Oxidation state represents the hypothetical charge an atom would have if all its bonds were ionic.

    * Rules:

    * The oxidation state of elemental atoms is always 0.

    * Fluorine always has an oxidation state of -1.

    * The sum of oxidation states in a neutral compound is 0.

    Applying the Rules

    1. Fluorine (F): Since there are six fluorine atoms (F₆), the total oxidation state from fluorine is -6.

    2. Platinum (Pt): The oxidation state of platinum is +6. This is because it needs to balance the -6 charge from the fluorine atoms to maintain a neutral compound.

    3. Oxygen (O): Since we have two oxygen atoms (O₂) and the compound is neutral, the total oxidation state from oxygen must be +6 (to cancel out the -6 from fluorine and +6 from platinum).

    * Therefore, the oxidation state of each oxygen atom is +3.

    Final Answer: The oxidation state of oxygen in O₂PtF₆ is +3.

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