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  • Equilibrium Expressions: Why Solids & Liquids Are Excluded
    Solids and liquids are not included in equilibrium expressions because their concentrations are considered constant in a heterogeneous equilibrium.

    Here's why:

    * Solids: The concentration of a solid is essentially its density, which is a fixed value under a given set of conditions. The amount of solid present doesn't change the concentration, so it doesn't affect the equilibrium.

    * Liquids: Similar to solids, the concentration of a pure liquid is also constant under specific conditions. For example, the concentration of pure water is always 55.5 M.

    Consider an example:

    The equilibrium reaction for the dissolution of calcium carbonate in water:

    ```

    CaCO3(s) <=> Ca²⁺(aq) + CO₃²⁻(aq)

    ```

    The equilibrium expression for this reaction is:

    ```

    K = [Ca²⁺][CO₃²⁻]

    ```

    You'll notice that CaCO3(s) is not included in the expression. This is because the concentration of solid CaCO3 remains constant, regardless of how much CaCO3 is present.

    Key points:

    * Heterogeneous equilibrium: This refers to an equilibrium involving substances in different phases (solid, liquid, gas).

    * Homogeneous equilibrium: This refers to an equilibrium involving substances in the same phase.

    In summary: Including solids and liquids in equilibrium expressions would make them dependent on the amount of substance present, which doesn't reflect the true nature of equilibrium in heterogeneous systems.

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