1. Calculate the empirical formula mass:

* C: 12.01 g/mol

* H: 1.01 g/mol

* Empirical formula mass of CH2: 12.01 + (2 * 1.01) = 14.03 g/mol

2. Determine the whole number ratio between the molar mass and the empirical formula mass:

* Molar mass / Empirical formula mass = 42.0 g/mol / 14.03 g/mol ≈ 3

3. Multiply the subscripts in the empirical formula by the ratio:

* CH2 * 3 = C3H6

Therefore, the molecular formula of the compound is C3H6.