1. Determine the molar mass of manganese (Mn):
* The molar mass of Mn is approximately 54.94 g/mol.
2. Calculate the moles of manganese in 0.1 g of the hydrated salt:
* Step 1: Find the mass percentage of Mn in the hydrated salt:
* Molar mass of MnSO₄·4H₂O = 223 g/mol (given)
* Mass percentage of Mn = (Molar mass of Mn / Molar mass of MnSO₄·4H₂O) * 100%
* Mass percentage of Mn = (54.94 g/mol / 223 g/mol) * 100% ≈ 24.6%
* Step 2: Calculate the mass of Mn in 0.1 g of the hydrated salt:
* Mass of Mn = 0.1 g * 24.6% = 0.0246 g
* Step 3: Calculate the moles of Mn:
* Moles of Mn = Mass of Mn / Molar mass of Mn
* Moles of Mn = 0.0246 g / 54.94 g/mol ≈ 0.000448 moles
Therefore, approximately 0.000448 moles of manganese are contained in 0.1 g of MnSO₄·4H₂O.
