Here's how to calculate the number of moles in 114 g of SbCl3:

1. Find the molar mass of SbCl3:

* Sb (Antimony) has a molar mass of 121.76 g/mol

* Cl (Chlorine) has a molar mass of 35.45 g/mol

* SbCl3 has a molar mass of 121.76 + (3 * 35.45) = 228.11 g/mol

2. Use the formula:

* Moles = Mass / Molar Mass

3. Calculate the moles:

* Moles = 114 g / 228.11 g/mol = 0.5 mol

Therefore, there are 0.5 moles in 114 g of SbCl3.