1. Determine the molar mass of KOH:

* K (Potassium) = 39.10 g/mol

* O (Oxygen) = 16.00 g/mol

* H (Hydrogen) = 1.01 g/mol

* Molar mass of KOH = 39.10 + 16.00 + 1.01 = 56.11 g/mol

2. Calculate the moles of KOH needed:

* Molarity (M) = moles of solute / liters of solution

* We have 2 M solution and 60 mL (0.06 L)

* Moles of KOH = 2 M * 0.06 L = 0.12 moles

3. Convert moles to grams:

* Grams of KOH = moles of KOH * molar mass of KOH

* Grams of KOH = 0.12 moles * 56.11 g/mol = 6.73 g

Therefore, you need 6.73 grams of solid KOH to prepare a 60 mL 2 M solution.