1. Write the balanced chemical equation:

Zn(s) + 2Pb(SO₄)₂(aq) → Zn(SO₄)₂(aq) + 2PbSO₄(s)

2. Determine the mole ratio:

The balanced equation shows that 1 mole of zinc (Zn) reacts to produce 2 moles of lead(II) sulfate (PbSO₄).

3. Calculate the moles of lead(II) sulfate produced:

Since we have 0.320 moles of zinc, and the mole ratio is 1:2, we will produce:

0.320 moles Zn * (2 moles PbSO₄ / 1 mole Zn) = 0.640 moles PbSO₄

4. Calculate the mass of lead(II) sulfate produced:

To convert moles of PbSO₄ to grams, we need the molar mass of PbSO₄:

* Pb: 207.2 g/mol

* S: 32.06 g/mol

* O: 16.00 g/mol (x 4)

Molar mass of PbSO₄ = 207.2 + 32.06 + (16.00 * 4) = 303.26 g/mol

Now, calculate the mass:

0.640 moles PbSO₄ * (303.26 g PbSO₄ / 1 mole PbSO₄) = 194.1 g PbSO₄

Therefore, 194.1 grams of lead(II) sulfate would be produced.