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  • Atom Count in Na₂S₂O₃·5H₂O: A Detailed Breakdown
    Here's how to determine the number of atoms in the formula Na₂S₂O₃·5H₂O:

    1. Break down the formula:

    * Na₂S₂O₃: This represents sodium thiosulfate.

    * 5H₂O: This represents five water molecules.

    2. Count the atoms in each part:

    * Na₂S₂O₃:

    * 2 sodium atoms (Na)

    * 2 sulfur atoms (S)

    * 3 oxygen atoms (O)

    * 5H₂O:

    * 10 hydrogen atoms (H) (5 molecules x 2 hydrogen atoms per molecule)

    * 5 oxygen atoms (O) (5 molecules x 1 oxygen atom per molecule)

    3. Add up the atoms from both parts:

    * Total atoms: 2 Na + 2 S + 3 O + 10 H + 5 O = 22 atoms

    Therefore, there are 22 atoms represented in the formula Na₂S₂O₃·5H₂O.

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