1. Write the balanced chemical equation:

2 NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + 2 H₂O(l)

2. Determine the moles of H₂SO₄:

* Convert the volume of H₂SO₄ from mL to L: 47.2 mL * (1 L / 1000 mL) = 0.0472 L

* Multiply the volume by the molarity to find the moles: 0.0472 L * 2.075 mol/L = 0.0979 mol H₂SO₄

3. Use the mole ratio from the balanced equation to find moles of NaOH:

* The mole ratio of NaOH to H₂SO₄ is 2:1.

* Moles of NaOH = 0.0979 mol H₂SO₄ * (2 mol NaOH / 1 mol H₂SO₄) = 0.1958 mol NaOH

4. Calculate the volume of NaOH solution:

* Divide the moles of NaOH by the molarity of the NaOH solution: 0.1958 mol NaOH / 1.336 mol/L = 0.1465 L NaOH

5. Convert the volume to mL:

* 0.1465 L * (1000 mL / 1 L) = 146.5 mL

Therefore, you would need 146.5 mL of 1.336 M NaOH solution to titrate 47.2 mL of 2.075 M H₂SO₄.