Molar Mass of Chalcopyrite (CuFeS₂) = 64 (Copper) + 56 (Iron) + 32 x 2 (Sulfur)
Molar Mass = 64 + 56 + 64 = 184 g/mol
Mass of Sulfur in Chalcopyrite = 2 x 32 g/mol (Since there are two sulfur atoms in the compound) = 64 g/mol
Percentage of Sulfur in Chalcopyrite = (Mass of Sulfur / Molar Mass of Chalcopyrite) × 100
Percentage of Sulfur = (64 g/mol / 184 g/mol) × 100 ≈ 34.78%
Therefore, the percentage of sulfur in chalcopyrite is approximately 34.78%.