Mass = Molarity x Volume x Molecular weight
Given:
Molarity (M) = 0.25 M
Volume (V) = 1 L (assuming we want to make 1 liter of the solution)
Molecular weight of ammonium sulfate ((NH4)2SO4) = 132.14 g/mol
1. Calculate the number of moles of ammonium sulfate needed:
Moles = Molarity x Volume
Moles = 0.25 mol/L x 1 L = 0.25 mol
2. Calculate the mass of ammonium sulfate:
Mass = Moles x Molecular weight
Mass = 0.25 mol x 132.14 g/mol = 33.04 g
Therefore, 33.04 grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M.
