Percent Carbon = (Mass of Carbon/ Molar Mass of Compound) x 100
Given the molecular formula C4H10O, we can determine the molar mass of the compound:
Molar Mass of C4H10O = (4 x Atomic Mass of Carbon) + (10 x Atomic Mass of Hydrogen) + (1 x Atomic Mass of Oxygen)
Molar Mass of C4H10O = (4 x 12.01 g/mol) + (10 x 1.01 g/mol) + (1 x 16.00 g/mol)
Molar Mass of C4H10O = 74.12 g/mol
Now, we can calculate the mass of carbon in the compound:
Mass of Carbon in C4H10O = (4 x Atomic Mass of Carbon)
Mass of Carbon in C4H10O = (4 x 12.01 g/mol) = 48.04 g
Finally, we can determine the percent of carbon by mass:
Percent Carbon = (Mass of Carbon/ Molar Mass of Compound) x 100
Percent Carbon = (48.04 g/mol / 74.12 g/mol) x 100
Percent Carbon ≈ 64.80%
Therefore, the percent of carbon by mass in C4H10O is approximately 64.80%.
