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  • Electron Count in Phosphate Ion (PO₄³⁻): A Detailed Explanation
    In the Lewis structure of phosphate ion (PO₄³⁻), there are a total of three extra electrons compared to the neutral molecule.

    Here's how to determine the extra electrons:

    Phosphorus atom: Phosphorus (P) has five valence electrons.

    Oxygen atoms: Each oxygen atom (O) has six valence electrons.

    Negative charge: The phosphate ion carries a 3- negative charge.

    Calculating Extra Electrons:

    Neutral molecule (PO₄):

    - Phosphorus: 5 valence electrons

    - Oxygen (4 atoms): 4 x 6 = 24 valence electrons

    Total valence electrons in neutral PO₄: 5 + 24 = 29 electrons

    Phosphate ion (PO₄³⁻):

    - Phosphorus: 5 valence electrons

    - Oxygen (4 atoms): 4 x 6 = 24 valence electrons

    - Negative charge: 3 extra electrons (from the 3- charge)

    Total valence electrons in PO₄³⁻: 5 + 24 + 3 = 32 electrons

    Extra Electrons:

    The difference between the valence electrons in the phosphate ion (32) and the neutral molecule (29) represents the extra electrons.

    32 valence electrons (PO₄³⁻) - 29 valence electrons (PO₄) = 3 extra electrons

    Therefore, the Lewis structure of phosphate ion (PO₄³⁻) has three extra electrons compared to the neutral molecule. These extra electrons are typically shown as negative charges around the oxygen atoms in the Lewis structure.

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