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  • Calculating Heat Removal for Ice Formation: A Step-by-Step Guide
    The amount of heat that needs to be removed to turn one pound of water at 32°F into a block of ice at 17°F can be calculated using the formula:

    Q = m * (Lf + C * (Tf - Ti))

    Where:

    - Q is the amount of heat that needs to be removed (in BTU)

    - m is the mass of water (in pounds)

    - Lf is the latent heat of fusion for water (144 BTU/lb)

    - C is the specific heat of water (1 BTU/lb-°F)

    - Tf is the final temperature of the ice (17°F)

    - Ti is the initial temperature of the water (32°F)

    Plugging in the values, we get:

    Q = 1 lb * (144 BTU/lb + 1 BTU/lb-°F * (17°F - 32°F))

    Q = 1 lb * (144 BTU/lb + 1 BTU/lb-°F * (-15°F))

    Q = 1 lb * (144 BTU/lb - 15 BTU/lb)

    Q = 129 BTU

    Therefore, 129 BTU's must be removed from one pound of water at 32°F in order to create a block of ice at 17°F.

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