2AgCH3COO(aq) + Na3PO4(aq) → Ag3PO4(s) + 3CH3COONa(aq)
From the equation, we can see that 2 moles of silver acetate react with 1 mole of sodium phosphate. The molar mass of silver acetate is 166.91 g/mol, and the molar mass of sodium phosphate is 163.94 g/mol. Therefore, 10g of silver acetate is:
10 g / 166.91 g/mol = 0.0599 mol
Since we have excess sodium phosphate, we can assume that all of the silver acetate will react. According to the balanced equation, 0.0599 mol of silver acetate will produce 0.0299 mol of silver phosphate. The molar mass of silver phosphate is 418.67 g/mol, so the mass of silver phosphate produced will be:
0.0299 mol * 418.67 g/mol = 12.54 g
Therefore, if 10g of silver acetate reacts with excess sodium phosphate, 12.54g of silver phosphate will be produced.
