$$\nu = \frac{c}{\lambda}$$
where:
- \(\nu\) is the frequency in Hertz (Hz)
- \(c\) is the speed of light in meters per second (m/s), which is approximately \(2.998 \times 10^8\) m/s
- \(\lambda\) is the wavelength in meters (m)
Given that the reaction line is at 460 nm, we need to convert it to meters:
$$ \lambda = 460 \text{ nm} = 460 \times 10^{-9} \text{ m}$$
Substituting the values into the formula, we can calculate the frequency:
$$ \nu = \frac{2.998 \times 10^8 \text{ m/s}}{460 \times 10^{-9} \text{ m}} \approx 6.52 \times 10^{14} \text{ Hz}$$
Therefore, the frequency corresponding to the reaction line at 460 nm is approximately \(6.52 \times 10^{14} \) Hz.
