The molar mass of I2 is 253.80 g/mol, and the molar mass of C Cl4 is 153.82 g/mol. To prepare a 0.20 m solution of I2 in C Cl4, we need to add 0.20 mol of I2 to 750 g of C Cl4.

The number of moles of I2 required is:

$$0.20 \text{ mol} = 0.20 \times 253.80 \text{ g/mol} = 50.76 \text{ g}$$

Therefore, 50.76 g of I2 should be added to 750 g of C Cl4 to prepare a 0.20 m solution.