The reaction can be represented by the following chemical equation:
2KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq)
In this reaction, the potassium ions (K+) and nitrate ions (NO3-) from potassium iodide and lead nitrate, respectively, remain unchanged and form potassium nitrate (KNO3). Meanwhile, the lead ions (Pb2+) from lead nitrate combine with iodide ions (I-) from potassium iodide to form lead iodide (PbI2).
Lead iodide is a bright yellow, insoluble compound that precipitates out of the solution. The precipitation of lead iodide can be observed as a cloudy or turbid appearance in the reaction mixture.
It's important to note that lead iodide is a toxic substance, and appropriate safety precautions should be taken when working with lead compounds.