To calculate the milliliters of 0.248M HCl required to react with 1.36 grams of zinc and produce hydrogen, we need to first determine the moles of zinc:

Moles of Zinc (Zn) = mass (in grams) / molar mass of Zn

The molar mass of Zn is 65.38 g/mol.

Moles of Zn = 1.36 g / 65.38 g/mol = 0.0208 mol

According to the balanced chemical equation for the reaction between zinc and HCl:

Zn + 2HCl -> ZnCl2 + H2

1 mole of Zn reacts with 2 moles of HCl. Therefore, 0.0208 mol of Zn will react with 2 * 0.0208 mol = 0.0416 mol of HCl.

Now we can use the molarity of HCl to calculate the volume required:

Molarity (M) = Moles (mol) / Volume (L)

Volume (in liters) = Moles / Molarity

Volume of HCl = 0.0416 mol / 0.248 M = 0.168 L

Finally, we convert liters to milliliters:

Volume of HCl = 0.168 L * 1000 mL/L = 168 mL

Therefore, 168 milliliters of 0.248M HCl are needed to react with 1.36 grams of zinc and produce hydrogen.