To calculate the molality of the solution, we need to determine the number of moles of solute (AgClO4) and the mass of the solvent (C6H6) in kilograms.

Step 1: Calculate the number of moles of AgClO4

The molar mass of AgClO4 is 192.38 g/mol.

Moles of AgClO4 = Mass / Molar mass

= 75.2 g / 192.38 g/mol

= 0.391 mol

Step 2: Convert the mass of C6H6 to kilograms

Mass of C6H6 = 885 g

= 0.885 kg

Step 3: Calculate the molality

Molality (m) = Moles of solute / Mass of solvent in kg

= 0.391 mol / 0.885 kg

= 0.442 mol/kg

Therefore, the molality of the solution is 0.442 mol/kg.