$$N_2 + 3H_2 \rightarrow 2NH_3$$
From the equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
The molar mass of N2 is 28 g/mol. Therefore, 14 grams of N2 is equal to:
$$14 \text{ g N}_2 \times \frac{1 \text{ mol N}_2}{28 \text{ g N}_2} = 0.5 \text{ mol N}_2$$
According to the stoichiometry of the balanced chemical equation, 1 mole of N2 produces 2 moles of NH3. Therefore, 0.5 moles of N2 will produce:
$$0.5 \text{ mol N}_2 \times \frac{2 \text{ mol NH}_3}{1 \text{ mol N}_2} = 1 \text{ mol NH}_3$$
Hence, 14 grams of N2 can produce 1 mole of NH3.
