To determine the moles of Zn consumed, we need to consider the stoichiometry of the reaction:

Zn + 2HCl → ZnCl2 + H2

From the balanced equation, we can see that 1 mole of Zn reacts with 2 moles of HCl. So, if 1.60 x 1024 molecules of HCl react, we can calculate the corresponding moles of HCl:

Moles of HCl = (1.60 x 1024 molecules HCl) / (6.022 x 1023 molecules/mol) ≈ 0.266 mol HCl

Since 1 mole of Zn reacts with 2 moles of HCl, we can determine the moles of Zn consumed:

Moles of Zn = (0.266 mol HCl) / (2 moles HCl/mole Zn) ≈ 0.133 mol Zn

Therefore, approximately 0.133 moles of Zn are consumed when 1.60 x 1024 molecules of HCl react completely in the given equation.