Step 1: Hydroboration
React 2-pentyne with borane (BH3), a source of hydrogen and boron, to form an organoborane intermediate. This step results in the addition of a BH2 group to the triple bond, forming a three-membered ring called a cyclic alkylborane.
Step 2: Oxidation
Next, we oxidize the cyclic alkylborane intermediate using hydrogen peroxide (H2O2), a source of oxygen, in the presence of sodium hydroxide (NaOH), a base. This oxidation step converts the boron-carbon bond into a carbon-oxygen bond, forming an alcohol intermediate.
Step 3: Protonation
Finally, we protonate the hydroxyl group of the alcohol intermediate using dilute hydrochloric acid (HCl). Protonation results in the loss of a water molecule (H2O) and the formation of a carbocation intermediate. This carbocation then undergoes rearrangement to form the more stable 1-pentene product.
The overall reaction can be summarized as follows:
```
2-Pentyne + BH3 -> Cyclic alkylborane intermediate
Cyclic alkylborane intermediate + H2O2 + NaOH -> Alcohol intermediate
Alcohol intermediate + HCl -> Carbocation intermediate
Carbocation intermediate -> 1-Pentene + H2O
```
By performing these steps, we can successfully convert 2-pentyne to 1-pentene through hydroboration-oxidation.