The reaction between barium chloride (BaCl2) and sodium hydroxide (NaOH) produces barium hydroxide [Ba(OH)2] and sodium chloride (NaCl). The chemical equation for this reaction is:

BaCl2 (aq) + 2NaOH (aq) → Ba(OH)2 (aq) + 2NaCl (aq)

In this reaction, barium chloride and sodium hydroxide are dissolved in water. Barium ions (Ba2+) from barium chloride react with hydroxide ions (OH-) from sodium hydroxide to form barium hydroxide. Sodium ions (Na+) from sodium hydroxide combine with chloride ions (Cl-) from barium chloride to form sodium chloride. The products of the reaction, barium hydroxide and sodium chloride, are both soluble in water and remain in solution.