From the balanced chemical equation, we can see that 3 moles of A2 react to produce 2 moles of D. So, for every 1 mole of A2 reacted, we can produce 2/3 moles of D. If we have 5.00 moles of A2, we can produce:

$$5.00\text{ mol A2}\times\frac{2\text{ mol D}}{3\text{ mol A2}}=\boxed{3.33 \text{ mol D}}$$