The solubility of MgO can be calculated using the Ksp expression:
Ksp = [Mg2+][OH-]^2
At equilibrium, the concentration of Mg2+ and OH- ions will be equal, so we can substitute [Mg2+] = [OH-] = x.
Ksp = x^3
x = [Mg2+] = [OH-] = (Ksp)1/3
Substituting the value of Ksp, we get:
x = (5.61 x 10-12)1/3 = 1.83 x 10-4 M
Therefore, the solubility of magnesium oxide in water at 25 °C is approximately 1.83 x 10-4 M.