1. Valence Electrons: Each hydrogen (H) atom has one valence electron, while the oxygen (O) atom has six.
2. Shared Electron Pairs: The two H atoms and the O atom share electrons in a covalent bond. Each H atom shares one electron with the O atom, and the O atom shares one electron with each H atom.
3. Electron Pairs and Molecular Structure: The shared electron pairs between the H and O atoms form two covalent bonds. The O atom, with four total valence electrons, forms two single bonds with the H atoms. This tetrahedral electron pair geometry results in a bent or angular molecular structure.
4. Lone Electron Pairs: The O atom also has two lone electron pairs, which are pairs of electrons that are not involved in bonding. These lone electron pairs occupy the remaining two corners of the tetrahedral electron pair geometry.
The electron arrangement of the water molecule can be summarized as follows:
- Two H atoms, each with one valence electron, forming single covalent bonds with the O atom.
- One O atom, with six valence electrons, sharing one electron with each H atom and having two lone electron pairs.
- Tetrahedral electron pair geometry, resulting in a bent or angular molecular structure.
This electron arrangement gives the water molecule its unique properties, including its polarity and hydrogen bonding capabilities.