The molar mass of boron (B) is 10.81 grams per mole. To calculate the number of moles in 97.2 grams of boron, we can use the formula:

Moles = Mass / Molar Mass

Moles = 97.2 grams / 10.81 grams per mole

Moles ≈ 9.002 moles

Therefore, there are approximately 9.002 moles in 97.2 grams of boron.