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  • Preparing a 0.25 M HCl Solution: A Step-by-Step Guide
    Step 1: Calculate the amount of HCl needed.

    The formula for calculating the amount of solute needed to prepare a solution of a specific concentration is:

    ```

    Moles of solute = Molarity (M) × Volume of solution (L)

    ```

    In this case, we want to prepare 1L of a 0.25 M solution of HCl. So, the moles of HCl needed are:

    ```

    Moles of HCl = 0.25 M × 1 L = 0.25 moles

    ```

    Step 2: Determine the mass of HCl needed.

    The molar mass of HCl is 36.46 g/mol. So, the mass of HCl needed to prepare 0.25 moles of solution is:

    ```

    Mass of HCl = Moles of HCl × Molar mass of HCl

    = 0.25 mol × 36.46 g/mol = 9.115 g

    ```

    Step 3: Prepare the solution.

    - Add 9.115 g of HCl to a 1L volumetric flask.

    - Add approximately 500 mL of deionized water to the flask.

    - Swirl the flask gently to dissolve the HCl.

    - Add more deionized water until the volume reaches the 1L mark.

    - Mix the solution thoroughly.

    The resulting solution will be 0.25 M HCl.

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