The reaction between ammonia and water can be represented by the following equation:
NH3 + H2O ⇌ NH4+ + OH-
The equilibrium constant for this reaction is:
Kb = [NH4+][OH-]/[NH3]
At 25°C, Kb = 1.8 × 10^-5. This means that for every mole of ammonia that dissolves in water, only 1.8 × 10^-5 moles of ammonium ions and hydroxide ions are produced.
The small amount of hydroxide ions that are produced are enough to make the solution basic. This is because hydroxide ions are strong bases, and they can completely dissociate in water to form hydrogen ions (H+) and hydroxide ions. The hydrogen ions that are produced by the dissociation of hydroxide ions react with water to form hydronium ions (H3O+). Hydronium ions are responsible for the acidity of solutions.
The pH of an aqueous solution of ammonia can be calculated using the following equation:
pH = 14 - pOH
The pOH of an aqueous solution of ammonia can be calculated using the following equation:
pOH = -log[OH-]
At 25°C, the pH of a 0.1 M solution of ammonia is 11.63. This means that the solution is basic.