PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Given the following values:
P = 0.914 atm
V = 0.325 L
T = 19 deg Celsius = 292 K
R = 0.08206 L atm / mol K
We can rearrange the ideal gas law to solve for n:
n = PV / RT
Substituting the given values:
n = (0.914 atm)(0.325 L) / (0.08206 L atm / mol K)(292 K)
n = 0.0129 moles
Therefore, there are 0.0129 moles of gas in the 0.325 liter container at the given conditions.
