1. The oxidation state of sodium (Na) is +1.
2. The oxidation state of oxygen (O) is generally -2.
3. Let the oxidation state of bromine (Br) be "x".
In a neutral compound, the sum of oxidation states of all atoms must be zero. Therefore, we can set up the equation:
+1 + x + 3(-2) = 0
Solving for "x", we get:
+1 + x - 6 = 0
x - 5 = 0
x = +5
Therefore, the oxidation state of bromine in NaBrO3 is +5.
