To determine the atom, we can use the Avogadro's number (Nₐ), which is 6.022x10^23 atoms per mole. The atomic mass of helium is approximately 4.0026 atomic mass units (amu).
We can convert the given mass to atomic mass units (amu) as follows:
Mass in amu = (2.67x10-24 g) / (1.6605x10-24 g/amu) ≈ 1.61 amu
Since the calculated atomic mass is closest to the atomic mass of helium (4.0026 amu), we can conclude that the atom with a mass of 2.67x10-24 g is helium (He).
