1. Calculate the moles of AgCl precipitated:
Moles of AgCl = mass of AgCl / molar mass of AgCl
Moles of AgCl = 6.21 g / 143.32 g/mol
Moles of AgCl = 0.0433 mol
2. Since AgCl is formed from the reaction of silver (Ag) and chloride (Cl) ions, the moles of AgCl are equal to the moles of Ag present in the coin. Therefore, the moles of Ag in the coin are 0.0433 mol.
3. Calculate the mass of Ag in the coin:
Mass of Ag = moles of Ag * molar mass of Ag
Mass of Ag = 0.0433 mol * 107.87 g/mol
Mass of Ag = 4.66 g
4. Calculate the percent of silver in the coin:
Percent of silver = (mass of Ag / total mass of coin) * 100
Percent of silver = (4.66 g / 6.80 g) * 100
Percent of silver ≈ 68.53%
Therefore, the coin contains approximately 68.53% silver.