At STP, 1 mole of any gas occupies 22.4 L. The molar mass of krypton (Kr) is 83.80 g/mol. To find the volume of 0.416 g of Kr gas at STP, we can use the following formula:

Volume = (mass of Kr / molar mass of Kr) * 22.4 L/mol

Volume = (0.416 g / 83.80 g/mol) * 22.4 L/mol

Volume ≈ 0.110 L

Therefore, 0.416 g of krypton gas will occupy approximately 0.110 L at STP.