1. Determine the theoretical yield of carbon disulfide.
2. Compare the actual yield (10.1 g) to the theoretical yield and express the result as a percentage.
1. Theoretical yield:
The balanced chemical equation for the reaction between sulfur dioxide and methane to produce carbon disulfide is:
```
CO2 + 2H2S ---> CS2 + 2H2O
```
From the equation, we can see that 1 mole of CO2 reacts with 2 moles of H2S to produce 1 mole of CS2.
The molar mass of CS2 is 76 g/mol.
Therefore, the theoretical yield of CS2 can be calculated as:
```
Theoretical yield = 33.4 g SO2 * (1 mol SO2 / 64 g SO2) * (1 mol CS2 / 1 mol SO2) * (76 g CS2 / 1 mol CS2)
= 40.9 g CS2
```
2. Percent yield:
The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying the result by 100.
```
Percent yield = (Actual yield / Theoretical yield) * 100
= (10.1 g CS2 / 40.9 g CS2) * 100
= 24.7%
```
Therefore, the percent yield of carbon disulfide is 24.7%.
