The expected product of the reaction between KOH and NI is potassium iodide (KI) and nitrogen gas (N₂).

The reaction can be represented as follows:

KOH + NI → KI + N₂ + H₂O

In this reaction, the hydroxide ion (OH⁻) from KOH reacts with the nitrogen iodide (NI) to form potassium iodide (KI) and water (H₂O). The nitrogen atom in NI is oxidized from an oxidation state of -3 to 0, while the iodine atom is reduced from an oxidation state of +1 to -1. The nitrogen gas (N₂) is a byproduct of the reaction.