HCl + KOH → KCl + H2O

Step 2: Convert the volume of HCl from milliliters to liters.

65 mL HCl = 0.065 L HCl

Step 3: Calculate the number of moles of HCl in the 0.065 L solution.

n(HCl) = c(HCl) × V(HCl)

n(HCl) = 0.15 mol/L × 0.065 L

n(HCl) = 0.00975 mol HCl

Step 4: Use the mole ratio from the balanced chemical equation to calculate the number of moles of KOH required to reach the equivalence point.

From the balanced chemical equation, we know that 1 mole of HCl reacts with 1 mole of KOH. Therefore, the number of moles of KOH required is also 0.00975 mol.

Step 5: Calculate the concentration of the KOH solution.

c(KOH) = n(KOH) / V(KOH)

c(KOH) = 0.00975 mol / 0.044 L

c(KOH) = 0.2216 mol/L or 0.222 M

Therefore, the concentration of the KOH solution is 0.222 M.