For example, in a reaction between KHCO3 and HCl, the following equation shows that 1 mole of KHCO3 reacts with 1 mole of HCl:
KHCO3 + HCl → KCl + H2O + CO2
If we want to ensure that all of the KHCO3 reacts, we can use a 10% excess of HCl. This means that we would use 1.1 moles of HCl for every 1 mole of KHCO3.
This excess of acid will ensure that all of the KHCO3 reacts, and that the reaction goes to completion.