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  • Acetone Volume Calculation: Determining Volume from Moles and Density
    The molar mass of acetone (CH3COCH3) is 58.08 g/mol.

    3.35 moles of acetone is equal to 3.35 moles * 58.08 g/mol = 194.87 g.

    The density of acetone is 0.851 g/mL, so the volume of 194.87 g of acetone is equal to 194.87 g / 0.851 g/mL = 228.45 mL.

    Therefore, 228.45 mL of acetone would be needed to obtain 3.35 moles of acetone.

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